Soal/Latihan Fungsi Invers pertemuan ke-11

 Soal

Jawab : 

1.
F(x) = 4x – 3 / 2x + 1

    Y = 4x – 3 / 2x + 1
    Y (2x + 1) = 4x – 3
    2xy + y = 4x – 3
    2xy – 4x = -3 – y
    X (2y – 4) = -3 – y
    X = -3 – y / 2y – 4
    f-1(x) = -3 – x / 2x – 4

2.
F(x) = 3x – 2 / 5x + 8
Y = 3x – 2 / 5x + 8
Y (5x + 8) = 3x – 2
5xy + 8y = 3x – 2
5xy – 3x = -2 – 8y
X (5y – 3) = -2 – 8y
X = -2 – 8y / 5y – 3
f-1(x) = -2x – 8x / 5x – 3

3.
f(x) = 8x + 3 / 2 – 4x
y = 8x + 3 / 2 – 4x
y (2 – 4x) = 8x + 3
2y – 4xy = 8x + 3
-4xy – 8x = 3 – 2y
X (-4y – 8) = 3 – 2y
X = 3 – 2y / -4y – 8
f-1(x) = 3 – 2x / -4x – 8

4.
y = 2x - 6
-2x = -y - 6
2x = y + 6
x = 1/2 y + 6
maka f -1(x) = 1/2 y + 3

5.
f-1(x) = -5 -3 / 2x - 1
f-1(x) = dx +b / cx - a